Lesson 265: The Eigenvalue Problem: Finding Invariant Directions

Introduction: Directions That Don't Rotate

When a matrix acts on most vectors, it changes both their magnitude and direction. But some special vectors only get stretched (or compressed)—their direction stays the same. These are eigenvectors, and their stretch factors are eigenvalues.

Definition

A nonzero vector \(|\psi\rangle\) is an eigenvector of operator \(\hat{A}\) with eigenvalue \(\lambda\) if:

\[\hat{A}|\psi\rangle = \lambda|\psi\rangle\]

The operator just scales the vector—it doesn't change its direction.

Why Eigenvalues Matter

Worked Examples

Example 1: Pauli Z Matrix

Find eigenvalues and eigenvectors of \(\sigma_z = \begin{pmatrix} 1 & 0 \\ 0 & -1 \end{pmatrix}\):

For \(|+\rangle = \begin{pmatrix} 1 \\ 0 \end{pmatrix}\): \(\sigma_z|+\rangle = \begin{pmatrix} 1 \\ 0 \end{pmatrix} = 1 \cdot |+\rangle\)

Eigenvalue: \(\lambda = +1\)

For \(|-\rangle = \begin{pmatrix} 0 \\ 1 \end{pmatrix}\): \(\sigma_z|-\rangle = \begin{pmatrix} 0 \\ -1 \end{pmatrix} = -1 \cdot |-\rangle\)

Eigenvalue: \(\lambda = -1\)

Example 2: Pauli X Matrix

\(\sigma_x = \begin{pmatrix} 0 & 1 \\ 1 & 0 \end{pmatrix}\)

The eigenvectors are \(|+_x\rangle = \frac{1}{\sqrt{2}}\begin{pmatrix} 1 \\ 1 \end{pmatrix}\) (eigenvalue +1) and \(|-_x\rangle = \frac{1}{\sqrt{2}}\begin{pmatrix} 1 \\ -1 \end{pmatrix}\) (eigenvalue -1).

Example 3: Non-Eigenvector

Is \(|\psi\rangle = \begin{pmatrix} 1 \\ 1 \end{pmatrix}\) an eigenvector of \(\sigma_z\)?

\[\sigma_z|\psi\rangle = \begin{pmatrix} 1 \\ -1 \end{pmatrix} \neq \lambda\begin{pmatrix} 1 \\ 1 \end{pmatrix}\]

No—the direction changed.

The Quantum Connection

When you measure an observable \(\hat{A}\), the only possible results are its eigenvalues. If the system is in eigenstate \(|a\rangle\), you get eigenvalue \(a\) with certainty. If it's in a superposition, the eigenvalue equation determines which outcomes are possible and measurement collapses the state to the corresponding eigenvector.